2x^2-55x-1500=0

Solution for 2x^2-55x-1500=0 equation:

2x^2-55x-1500=0

a = 2; b = -55; c = -1500;
Δ = b2-4ac
Δ = -552-4·2·(-1500)
Δ = 15025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15025}=\sqrt{25*601}=\sqrt{25}*\sqrt{601}=5\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-5\sqrt{601}}{2*2}=\frac{55-5\sqrt{601}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+5\sqrt{601}}{2*2}=\frac{55+5\sqrt{601}}{4}
$